Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
Answer:
Not sure sorry Im really bad at this stuff
Step-by-step explanation:
Okay. so we need 15 2/5 pound bags. We'll calculate how many pounds that actually comes to. Our problem is 15x2/5. Using cross simplification, our problem becomes 3x2. 3x2=6. We need 6 pounds. That means that we must have 6 1-pound bags to fit with no leftovers.
Answer: The function that models the distance they drive is
f(x) = 50x + 20 where x is the time in hours
reasonable domain: 0 ≤ x ≤ 3
Step-by-step explanation:
examples:
95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.
120 = 50(2) + 20 This means that after 2 more hours they will reach their destination.
There is a little ambiguity in the question. The function could be written as if they are starting out. f(x) = 50t
20 = 50(.4) At 50 mph it took .4 hours to go 20 miles.
120 = 5(2.4) The whole trip took 2.4 hours.
Answer:
22/15 quarts of water.
Step-by-step explanation:
To solve this, we need to add 4/5 and 2/3. To do this, we need to find the LCM of 5 and 3. The LCM of 5 and 3 is 15. Now, we multiply 4/5 by 3/3. That gets us 12/15. Now, we multiply 2/3 by 5/5. That gets us 10/15. Now, we add 12/15 and 10/15 (don't add the bottom numbers). This gets us 22/15 quarts of water.
