(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
I think it would be 9 miles.
Simplify by dividing the two by 14
R = 3(t+4) + 1
Hope it helps
Answer:
To solve this inequality you need to get m by itself
3m+10<30 (First subtract 10 from each side)
3m<20 (10-10=0, 30-10=20) (Then divide each side by 3)
m< 20/3 or 6.666666
So your answer is any that is less than 6.66666
Your answer would be 5
5
Hope this helps ;)
