Answer:
count_land = count_air = count_water = 0
while True:
s = input("Enter a string: ")
if s == "xxxxx":
break
else:
if s == "land":
count_land += 1
elif s == "air":
count_air += 1
elif s == "water":
count_water += 1
print("land: " + str(count_land))
print("air: " + str(count_air))
print("water: " + str(count_water))
Explanation:
*The code is in Python
Initialize the variables
Create a while loop that iterates until a specific condition is met. Inside the loop, ask the user to enter the string. If it is "xxxxx", stop the loop. Otherwise, check if it is "land", "air", or "water". If it is one of the given strings, increment its counter by 1
When the loop is done, print the number of strings entered in the required format
Answer:
The code is not dereferencing the pointers. You have to place an asterisk in front of the pointer to read the value the pointer points to.
Explanation:
So "if (str1 != str2)" must be "if (*str1 != *str2)".
likewise:
while (*str1 != 0 && *str2 != 0)
and
result = (*str1 == *str2);
Program p1;
var a,b,c,d : integer; {i presume you give integer numbers for the values of a, b, c }
x1, x2 : real;
begin
write('a='); readln(a);
write('b='); readln(b);
write('c=');readln(c);
d:=b*b - 4*a*c
if a=0 then x1=x2= - c/b
else
if d>0 then begin
x1:=(-b+sqrt(d)) / (2*a);
x2:=(-b - sqrt(d))/(2*a);
end;
else if d=0 then x1=x2= - b /(2*a)
else write ("no specific solution because d<0");
writeln('x1=', x1);
writeln('x2=',x2);
readln;
end.
