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frosja888 [35]
3 years ago
11

Find an angle 0 coterminal to 701°, where 0°

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Answer:

  • 341°
  • -19°

Step-by-step explanation:

Subtracting 360°, you get ...

  701° -360° = 341°

Subtracting 360° again, you get ...

  341° -360° = -19°

Angles 341° and -19° are coterminal with 701°.

_____

<em>Additional comment</em>

You can find additional angles by adding or subtracting multiples of 360°. We presume you require an angle in a specific range. Hopefully this gives you enough information to help you find the angle you're looking for.

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keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of the equation above anyway?

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\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-1\implies \cfrac{-1}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{-1}}\qquad \stackrel{negative~reciprocal}{\cfrac{1}{1}\implies 1}}

so we're really looking for the equation of a line whose slope is 1 and runs through (-5,-6).

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-6})~\hspace{10em} \stackrel{slope}{m}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{1}[x-\stackrel{x_1}{(-5)}] \\\\\\ y+6=1(x+5)\implies y+6=x+5\implies y=x-1

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Logarithmic functions and exponential functions are inverse and opposite of one another

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