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horsena [70]
3 years ago
8

If anything, I need help with the whole page.

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0
I can't see the page, however if you need help with the whole thing, we could possibly message each other on here OR if you are comfortable, we could email.

I don't know what math you're in though because I can't see the page but I'm sure I can help you. I'm in calculus.

Best wishes!
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To make orange fizz, Noah mixes 4 scoops of powder with 6 cups of water. Andre mixes 5 scoops of powder with 8 cups of water.
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Noah's recipe because he uses less water per scoop of powder than Andre does.

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4 examples of one step equation
Mkey [24]

Answer:

Step-by-step explanation:

x + 14 = 20

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37 + (-37) im looking for the answer
Ksju [112]

Answer:

0

Step-by-step explanation:

37 + (-37)

open the bracket

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3 years ago
Find a matrix representation of the transformation L(x, y) = (3x + 4y, x − 2y).
mario62 [17]

Answer:

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Step-by-step explanation:

The general matrix representation for this transformation would be:

\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Solving the matrix product you have that the members of the result matrix are:

3x+4y = a*x + c*y

x - 2y = b*x + d*y

So the matrix A should be:

\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]

8 0
3 years ago
Triangle ABC, with vertices A(5,2), B(7,6), and C(2,5), is drawn inside a rectangle, as shown below.
natka813 [3]

Answer:

9 units²

Step-by-step explanation:

calculate the area of Δ ABC as

area of rectangle - area of 3 outer right triangles

area of rectangle = 5 × 4 = 20 units²

area of left Δ = \frac{1}{2} × 3 × 3 = 4 \frac{1}{2} units²

area of Δ on right = \frac{1}{2} × 2 × 4 = 4 units²

area of top Δ = \frac{1}{2} × 5 × 1 = 2\frac{1}{2} units²

Then

area of Δ ABC = 20 - 4 \frac{1}{2} - 4 - 2 \frac{1}{2} = 20 - 11 = 9 units²

8 0
2 years ago
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