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vazorg [7]
4 years ago
13

Quiz

Mathematics
1 answer:
ivanzaharov [21]4 years ago
4 0

Answer: Its A, Your Welcome.

Step-by-step explanation:

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First correct response gets brainliest
Simora [160]

Answer:

x = 13

Step-by-step explanation:

This question is based on Secant Secant theorem.

Secant Secant theorem gives us the following formula:

(AB + BD)AB = (AC + CE).AC

From the above question we have the following parameters

AB = 5

BD = x

AC = 7.5

CE = 4.5

Hence,

(AB + BD)AB = (AC + CE).AC

(5 + x)5 = (7.5 + 4.5)7.5

25 + 5x = 90

Collect like terms

5x = 90 - 25

5x = 65

x = 65/5

x = 13

5 0
3 years ago
Liz earns a salary of $2,200 per month, plus a commission of 5% of her sales. She wants to earn at least
serg [7]

Answer:

2200 + 0.5x >= 2500

Step-by-step explanation:

x is the amount of sales

7 0
2 years ago
Need help asap please ​
nalin [4]

Answer:

15 yd^2

Step-by-step explanation:

a= 1/2bh

a= 1/2(3)10

a= 1/2(30)

a= 15

8 0
3 years ago
Read 2 more answers
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
How do you solve this?
Pani-rosa [81]

a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt[4]{3^2}=3^\frac{2}{4}=3^\frac{1}{2}=\sqrt3

7 0
3 years ago
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