Answer:
Mr. Wright taught 1,050 students in 25 years.
Step-by-step explanation:
Given,
The number of students Mr. Wright taught = 18,
Also, every year the number of student is increased by 2,
So, in second year, the number of students = 18 + 2 = 20,
In third year = 20 + 2 = 22,
In fourth year = 22 + 2 = 24,
.............., so on,
Hence, we get an A.P. that shows the given situation,
18, 20, 22, 24, ............. till 25 years.....
First term, a = 18,
Common difference, d = 2,
And, number of terms, n = 25,
Hence, the total number of students that have been taught by him are,
Third option is correct.