This is not possible. Why not? Because the smallest the variance can get is 0.
Recall that 's' represents the standard deviation, so s^2 is the variance. It basically measures how spread out the values are. The higher the variance, the more spread out the data. You can think of it as "average distance from the mean". If the variance is 0, then all of the values are at the same point. So you could have a list like {2,2,2,2,2} which has variance 0. We cannot get any smaller variance than that. If your teacher insists all the values in the list are different, then the variance will be greater than 0.
Since x is across from 148, and arcs opposite inscribed angles = 2×angle, then we can find x first.
We could set the 2 angles equal to 180 or their arcs equal to 360.
360 - (2×148) = x-arc
x-arc = 360 - 296 = 64
x = x-arc ÷2 = 64/2 = 32
Now for angle A we plug in for x:
A = 2x+1 = 2(32)+1 = 65°
Answer:
v = 
Step-by-step explanation:
Given
t = 
( multiply both sides by 4 to clear the fraction )
4t = 3v + 1 ( subtract 1 from both sides )
4t - 1 = 3v ( divide both sides by 3 )
= v
