Find the equation of the line perpendicular to the 13x-3y=9 and passing through (-5,0)

Mathematics

1 answer:

aev [14]2 years ago

8 0

9514 1404 393

Answer:

x +4y = -5

Step-by-step explanation:

The equation of the perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. The new constant can be found by substituting the point values into the equation.

3x +12y = 3(-5) +12(0)

3x +12y = -15

We notice that all of the values include a factor of 3. We can divide that out to put the equation in standard form:

x + 4y = -5

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