Answer:
Maybe I know too much chemistry but how the metals (and the non-metals) react depends on where they are in the Periodic Table. The metals in groups I and II over on the far left side are explosively reactive and loose electrons and form ionic bonds. Examples: Na+1 has lost 1 electron and Li+2 has lost 2 electrons. The metals in the higher groups are more confusing but most of them share outer shell electrons and form covalent bonds. Examples: Fe2O3 (rust) where Iron shares 2X3 electrons with Oxygen which shares 3X2 electrons. Confused enough? :-)
The answer you'll be expected to give depends on the subject of the chapter you're studying. If you're studying covalent bonds, then the answer will probably be "form covalent bonds". If you're studying ionic bonds, then the answer will be "lose electrons".
Explanation:
This may not be the answer... I'm sorry if it's not
The empirical formula is C₂H₃O₂
<h3>What is Empirical formula of a compound ?</h3>
The empirical formula is the simplest whole number ratio of elements present in a compound.
The total molar mass of the compound is 118.084 g/mol.
mass of Carbon present = 40.6
mass of Hydrogen present = 5.1 grams
mass of Oxygen present = 2 grams
Moles of C = 40.6/12 = 3.38
Moles of H = 5.1/1.008 = 5
Moles of Oxygen = 54.2/15.999 = 3.38
Ratio of Moles of C to Oxygen is 1 : 1
Ratio of Moles of C to H is 1/1.5
Multiplying each mole fraction by 2
The empirical formula is C₂H₃O₂
To know more about Empirical Formula
brainly.com/question/14044066
#SPJ1
C. <span>High temperatures make the gas molecules move more quickly.
</span>
Answer:
Density is a physical quantity, defined as the ratio of body mass to the volume occupied by this body. The average body density is the ratio of body weight to its volume.
Since the mass in a body can be distributed unevenly, a more adequate model defines the density at each point of the body as a derivative of mass over volume.
Thus, to obtain the density of a sample, its mass must be divided by its volume. Thus, the density of the sample is 1.2 / 1.1, that is, 1.09 g/cm3.
Answer:
ΔH°(f) = -110.5 Kj/mole (exothermic)
Explanation:
C + 1/2O₂ => CO
This is asking for the 'Standard Heat of Formation (ΔH°(f)* for carbon monoxide (CO). Values for many compounds can be found in the appendix of most college general chemistry text books. From Ebbing & Gammon, 11th edition, General Chemistry, Appendix C, page 8A.
*Standard Heat of Formation by definition is the heat gained or lost on formation of a substance (compound) from its basic elements in standard state.
The ΔH°(f) values as indicated are found in the appendix of most college chemistry texts. By choosing any compound, one can determine the standard heat of formation equation for the substance of interest. For example, consider Magnesium Carbonate; MgCO₃(s).The basic standard states of each element is found in the Appendix on Thermodynamic Properties for Substances at 25°C & 1 atm. having ΔH°(f) values = 0.00 Kj/mole. All elements in standard state have a 0 Kj/mol. See appendix and note that under the ΔH°(f) symbol some substances have 0.00 Kj/mol values. The associated element will be in basic standard state,
Standard Heat of Formation Equation for formation of Magnesium Carbonate;
Mg°(s) + C°(gpt)* + 3/2O₂(g) => MgCO₃(s) ; ΔH°(f) = -1111.7 Kj/mole
* gpt => graphite
