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Lady bird [3.3K]
3 years ago
7

How to write a lap conclusion

Chemistry
1 answer:
iris [78.8K]3 years ago
5 0
Describe how the lab went , any complication that happened, any rules or laws used in the lab 
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Help How many atoms of hydrogen(gas) form if 10 grams of aluminum react? 2Al + 6HCl = 2AlCl3 + 3H2
arlik [135]

Answer: 3.35x10²³atoms H2

Explanation: solution attached:

Convert mass of Al to moles

Do the mole to mole ratio between Al and H2

Convert moles of H2 to atoms using Avogadro's number.

4 0
3 years ago
At what temperature would a 1.50 m nacl solution freeze, given that the van't hoff factor for nacl is 1.9? kf for water is 1.86
IRINA_888 [86]
Win to ki ne lei ma ki mna mata ki ss kk
5 0
3 years ago
In the laboratory, a general chemistry student measured the pH of a 0.486 M aqueous solution of triethanolamine, C6H15O3N to be
STatiana [176]

Answer:

Kb = 6.22x10⁻⁷

Explanation:

Triethanolamine, C₆H₁₅O₃N, is in equilibrium with water:

C₆H₁₅O₃N(aq) + H₂O(l) ⇄ C₆H₁₅O₃NH⁺(aq) + OH⁻(aq)

Kb is defined from concentrations in equilibrium, thus:

Kb = [C₆H₁₅O₃NH⁺] [OH⁻] / [C₆H₁₅O₃N]

The equilibrium concentration of these compounds could be written as:

[C₆H₁₅O₃N] = 0.486M - X

[C₆H₁₅O₃NH⁺] = X

[OH⁻] = X

pH is -log [H⁺], thus, [H⁺] = 10^-pH = 1.820x10⁻¹¹M

Also, Kw = [OH⁻] ₓ [H⁺];

1x10⁻¹⁴ = [OH⁻] ₓ [H⁺]

1x10⁻¹⁴ = [OH⁻] ₓ [1.820x10⁻¹¹M]

5.495x10⁻⁴M = [OH⁻], that means <em>X = 5.495x10⁻⁴M</em>

Replacing in Kb formula:

Kb = [5.495x10⁻⁴M] [5.495x10⁻⁴M] / [0.486M-5.495x10⁻⁴M]

<em>Kb = 6.22x10⁻⁷</em>

<em></em>

5 0
2 years ago
Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.
Anvisha [2.4K]

Answer : The rate law for the overall reaction is, Rate=k[NO]^2[H_2]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : 2NO+H_2\rightarrow N_2+H_2O_2    (slow)

Step 2 : H_2O_2+H_2\rightarrow 2H_2O     (fast)

Overall reaction : 2NO+2H_2\rightarrow N_2+2H_2O

The rate law expression for overall reaction should be in terms of NO\text{ and }H_2.

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

2NO+H_2\rightarrow N_2+H_2O_2

The expression of rate law for this reaction will be,

Rate=k[NO]^2[H_2]

Hence, the rate law for the overall reaction is, Rate=k[NO]^2[H_2]

8 0
3 years ago
Help meeeeehahahshshs
natka813 [3]
What grade are you in I’m in 9th ;-;
7 0
3 years ago
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