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Alisiya [41]
3 years ago
7

What are humic acids?

Chemistry
1 answer:
Dominik [7]3 years ago
5 0

Answer:

Los ácidos húmicos son restos de vida orgánica totalmente descompuestos. Son moléculas de cadena larga que son de alto peso y de color marrón oscuro. No son un solo ácido. Más bien, "ácido húmico" es un término amplio que se refiere a una mezcla compleja de muchos ácidos diferentes que son solubles en soluciones alcalinas. Existen de forma natural como parte del ciclo de vida de la naturaleza en suelos, océanos y arroyos. Cómo se forman?

Cuando las plantas y los animales mueren, sus moléculas quedan disponibles en el suelo para ser utilizadas por otros organismos. Bacterias, hongos, protozoos, lombrices de tierra e incluso insectos consumen el material fresco. Después de largos períodos de tiempo, cuando la materia en descomposición se ha comido y transformado a través de varios ciclos, lo que queda es un material resistente que resiste una mayor descomposición, llamado humus. (Este proceso se conoce como "humificación"). El humus es un término general que se refiere a compuestos estables y altamente complejos que son resistentes a una mayor descomposición. Y el humus consta de tres componentes: ácidos húmicos, ácidos fúlvicos y humus. Los ácidos húmicos y fúlvicos han demostrado ser invaluables para entornos de suelo saludables, particularmente por sus contribuciones a la estructura del suelo y la transferencia de nutrientes entre el suelo y las plantas.

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A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution
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<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure water = 100°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.52°C/m.g

m_{solute} = Given mass of solute (urea) = 27.0 g

M_{solute} = Molar mass of solute (urea) = 60 g/mol

W_{solvent} = Mass of solvent (water) = 150.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=1\times 0.52^oC/m\times \frac{27\times 1000}{60\times 150}\\\\\text{Boiling point of solution}=101.56^oC

Hence, the boiling point of solution is 101.56°C

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4 years ago
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