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Alisiya [41]
3 years ago
7

What are humic acids?

Chemistry
1 answer:
Dominik [7]3 years ago
5 0

Answer:

Los ácidos húmicos son restos de vida orgánica totalmente descompuestos. Son moléculas de cadena larga que son de alto peso y de color marrón oscuro. No son un solo ácido. Más bien, "ácido húmico" es un término amplio que se refiere a una mezcla compleja de muchos ácidos diferentes que son solubles en soluciones alcalinas. Existen de forma natural como parte del ciclo de vida de la naturaleza en suelos, océanos y arroyos. Cómo se forman?

Cuando las plantas y los animales mueren, sus moléculas quedan disponibles en el suelo para ser utilizadas por otros organismos. Bacterias, hongos, protozoos, lombrices de tierra e incluso insectos consumen el material fresco. Después de largos períodos de tiempo, cuando la materia en descomposición se ha comido y transformado a través de varios ciclos, lo que queda es un material resistente que resiste una mayor descomposición, llamado humus. (Este proceso se conoce como "humificación"). El humus es un término general que se refiere a compuestos estables y altamente complejos que son resistentes a una mayor descomposición. Y el humus consta de tres componentes: ácidos húmicos, ácidos fúlvicos y humus. Los ácidos húmicos y fúlvicos han demostrado ser invaluables para entornos de suelo saludables, particularmente por sus contribuciones a la estructura del suelo y la transferencia de nutrientes entre el suelo y las plantas.

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11.375 g ethylene is consumed if 35.0 grams of oxygen is allowed to react and 7.875 ml of water will be produced when the 35.0 grams of oxygen is allowed to react.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

According to the chemical equation for the combustion of ethylene, 5

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m_{_C_2_H_2}  = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{26g}{1 mol }

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m_{_H_2_O} = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{18g}{1 mol }

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Given that the density of water is 1.0g ml^{-1}, therefore

Density = \frac{Mass \;of \;water}{Volume \;of \;water}

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The volume of water = 7.875 ml

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