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tangare [24]
3 years ago
8

Mercury has a density of 13.6 g/cm^3 . What volume of mercury will have a mass of 47 grams? It’d be very helpful if someone coul

d please answer this question. If you could, please put the steps!
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Density = mass / volume

Givens

Density = 13.6 grams / cm^3

mass = 47 grams.

Solve

D = m/v

13.6 = 47 / volume Multiply by volume

13.6 * volume = 47 Divide by 13.6

volume = 47 / 13.6

Volume = 3.46 ccs

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What's next in this series: 324, 256, 196, 144?​
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Next term will be 100

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hope it helps

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2 years ago
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0.4x - 1.2 = 0.15x + 0.8 ?????????
valentina_108 [34]

Answer:

x = 8

Step-by-step explanation:

0.4x - 1.2 = 0.15x + 0.8

0.4x - 1.2 + 1.2 = 0.4x

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0.4x = 0.15x + 2

0.4x - 0.15x = 0.25x

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A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were
quester [9]

Answer:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

7 0
3 years ago
How many solutions are there<br><br><br>2x - y = 1<br>- 4x + y = 1​
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infinitely many solutions

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