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Elanso [62]
3 years ago
15

Please help thankyou ​brainiest peopleplease please please please please

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
4 0
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ To find the mean you add together the values and divide by how many values there are:

150 + 100 + 120 + 200 + 180 + 300 + 250 = 1300

1300/7 = 185.714285

Median:

Order the values and find the middle one:

100, 120, 150, 180, 200, 250, 300

As you can see, it is 180

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

USPshnik [31]3 years ago
3 0

Answer:

a) The mean is 185.714.

b) The median is 180.

Step-by-step explanation:

a) To find the mean, you add up all of the numbers and divide the sum by the amount of numbers added:

150 + 100 + 120 + 200 + 180 + 300 + 250 ÷ 7 = 185.714

(I don't know if you are rounding or need decimals, so I will include them.)

b) To find the medium, you line up all of the numbers by least to most value and find the middle number. If there is an odd amount of numbers, you just take the middle number. If there are an even amount of numbers, you take the two middle numbers and find the mean of them both.

100, 120, 150, 180, 200, 250, 300

                        ↑

                   Median

Have a good day, please mark this as Brainliest!

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Flura [38]

the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Condition for the parallel lines.

L1,  ax + bx + c = 0

L2, dx + ey + f = 0

If \rm \dfrac{a}{d} = \dfrac{b}{e} = \dfrac{c}{f} then lines have infinitely many solutions.

<h3>Which system of equations below has infinitely many solutions?</h3>

y = –3x + 4 and 3y = –9x + 12

On comparing we have

a = -3 , b = 1, and c = 4

d = -9 , e = 3, and f = 12

Then their ratio will be

\rm \dfrac{1}{3} = \dfrac{-3}{-9} = \dfrac{4}{12}\\\\\rm \dfrac{1}{3} = \dfrac{1}{3} = \dfrac{1}{3}

Hence  y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.

Thus the option B is correct.

More about the linear system link is given below.

brainly.com/question/20379472

7 0
2 years ago
Table
viktelen [127]

4) The first and second terms for both ratios need to be in the same order.

Step-by-step explanation:

Given ratio is:

16:36

In order to find any ratio equivalent to given ratio, the ratio can be divided by a number or multiplied to a number.

The equivalent ratio that is given: 72:32

If we multiply the given ratio by 2: We get 32:72

So,

Looking at the options we can conclude that the right answer is

4) The first and second terms for both ratios need to be in the same order.

Keywords: Ratio, Fractions

Learn more about ratios at:

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3 0
3 years ago
How do you solve 0.75(8+e)=2−1.25e ?
mash [69]
Distribute first.
.75 times 8 + .75 times e, which is 6+.75e = 2-1.25e
Then subtract 2 from both sides,
4+.75n=-1.25e
Next subtract .75 from both sides,
4=-2e
Divide both sides by -2, and you will get e= -2. Hope this helps!

6 0
3 years ago
Write an exponential equation in the form y = abx whose graph passes through points (4, 8) and (6, 32).
Artist 52 [7]

Answer:

Option C.

Step-by-step explanation:

The general exponential equation is

y=ab^x

It is given that the graph of exponential function passes through points (4,8) and (6,32). It means the equation of exponential function must be satisfied by these points.

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32=ab^6       ...(2)

Divide equation (2) by equation (1).

\dfrac{32}{8}=\dfrac{ab^6}{ab^4}

4=b^2

Taking square root on both sides.

2=b

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Substitute a=0.5 and b=2 in the given general exponential equation.

y=0.5(2)^x

Therefore, the correct option is C.

8 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

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i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

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n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

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