Answer:
b) 2.45
Step-by-step explanation:
The Euclidean distance in 3-space is the root of the sum of the squares of the x-, y-, and z-differences between the points.
<h3>Application</h3>
For the given points ...

The distance between x and y is ...

It’s 3 keidiskdkkskskskkssiisisisisiis
- Here the line is parallel to x axis
- Slope (m) will be tan(0)=0
- Y intercept is 1.
Y is constant.
The equation of line will be