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3 years ago

A rational number is

1 answer:

3 0

According to Google.com, a rational number is “a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.”

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The equations x minus 2 y = 4, 4 x + 5 y = 8, 6 x - 5 y = 15, and x + 2 y = 0 are shown on the graph below. On a coordinate plan

mihalych1998 [28]

x + 2 y = 0 is the equation that has the value (1.8, -0.9).

<u>Step-by-step explanation:</u>

The solution is (1.8,-0.9) and the given equations are

x-2y= 4....... 1

4x+5y= 8.....2

6x-5y=15.....3

x+2y=0........4

Substitute the solution in all the equations and equate the resulting values.

∴ Substitute (1.8, -0.9) in equation 1.

1.8-2(-0.9) = 4.

1.8 + 1.8 = 4.

3.6 ≠ 4.

Substitute (1.8, -0.9) in equation 2.

4(1.8)+5(-0.9)=8

7.2-4.5=8.

2.7≠8.

Substitute (1.8, -0.9) in equation 3.

6(1.8)-5(-0.9)=15.

10.8 + 4.5=15

15.3≠15.

Substitute (1.8, -0.9) in equation 4.

1.8+2(-0.9)=0.

1.8-1.8=0.

0=0.

∴x + 2 y = 0 is the equation that has the value (1.8, -0.9).

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3 years ago

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Let A = {10, 20, 30, 40, 50, 60} and B = {10, 40, 60}. What is A ∩ B?

erastovalidia [21]

This means common members {10,40,60}

5 0

3 years ago

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An owl begins at rest on a tree branch searching for prey. Once the owl locates the prey it flies from its perch and four second

aleksklad [387]

Answer: 1.4 m/s

Explanation: the acceleration equation is a = change in velocity/change in time.

Plug the values in and you get 5.6/4

Divide and get 1.4 m/s

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3 years ago

The width x of your iris decreases from 4 millimeters to 2 millimeters when you enter a dark room. How many times greater is the

inysia [295]

Answer:

The area of the Iris is 4 times greater.

Step-by-step explanation:

Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!

The average radius of the iris is 6mm, so we take this value.

Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

$6mm-4mm=2mm$

Therefore it's area $A$ is:

$A=\pi r^2=\pi (2)^2=4\pi$

When the iris contracts to 2mm, the radius of the pupil becomes:

$6mm-2mm=4mm$

Then it's area is $A$ :

$A=\pi r^2=\pi (4)^2=16\pi$

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

$\frac{16\pi }{4\pi } =4$

This is 4 times greater than the initial area.

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3 years ago

Test each statement below to see if it is reversible. If so, write it as a true biconditional. If not, write not reversible

FinnZ [79.3K]

Statement: Complementary angles are two angles with measures that have a sum of 90.
Reverse: Two angles with measures that have a sum of 90 are complementary angles.

Here the reverse is true, therefore, the statement is true biconditional.

Statement: A rectangle is a four-sided figure with at least one right angle.
Reverse: A four sided figure with at least one right angle is a rectangle.

Here, the reverse is not true, therefore, the statement is not reversible.

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3 years ago

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