Find the ratio of book price to number of pages for each ordered pair. Round your answer to the nearest hundredth

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

GrogVix [38]

Answer:

D. f^-1(x) = log2(x -6)
4x^2 -3 . . . . x ≤ 0
B. √(x^5) -3√(x^3) -18√x

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

<em>Every term</em> will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

7 0

3 years ago

Read 2 more answers

the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me

Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c) i) 3

ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey. At the start of the 50 seconds the speed is k metres per second. The distance travelled during the 50 seconds is 1.35 kilometres.

(a) Work out the average speed of the vehicle during the 50 seconds

(b) Work out the value of k.

(c) (i) Calculate the gradient of the graph in the final 10 seconds of the journey

(ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

$Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s$

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

$Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/s$ c) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

$Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40} \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3$

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

6 0

3 years ago

Identify the radicand in the radical below

Elena L [17]

Answer:

The radicand is whatever is under the the radical, so in this case, your answer would be D. 3x-5

4 0

3 years ago

]This problem is for my math class<br> Solve the inequality below<br> 6x - 5 < 55

trasher [3.6K]

Answer: x < 10

Step-by-step explanation: Just like any of your two-step equations, in this inequality, start by isolating the x term which in this case is 6x by adding 5 to both sides.

That leaves you with 6x < 60 and now just divide both sides by 2 and x < 10.

Notice that because we divide both sides of the inequality

by a positive number, not a negative, we did not change the

direction of the inequality sign.

Finally, put your answer in set notation, {x: x < 10}.

Unlike an equation which normally has one solution, the answer to an inequality must be stated as a solution set because an entire set of answers will work. In this problem, it's any number less than 10.

4 0

3 years ago

Debbie set a goal to run 6 miles. On Monday she ran 2.6 miles and on Tuesday she ran 1.75 miles. How far would Debbie need to ru

Makovka662 [10]

She will need to run 1.65 to reach her go

7 0

3 years ago