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yan [13]
3 years ago
10

A plane flew for six hours. For two hours the average speed was 264mph. For four hours the average speed was 490mph. How far did

the plane travel in six hours?
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

  2488 miles

Step-by-step explanation:

The relevant relationship is ...

  distance = speed × time

For each leg ...

  distance 1 = (264 mi/h) × (2 h) = 528 mi

  distance 2 = (490 mi/h) × (4 h) = 1960 mi

Then the total distance traveled in the 6 hours is ...

  distance traveled = distance 1 + distance 2 = 528 mi + 1960 mi

  distance traveled = 2488 mi

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Answer:

1846

Step-by-step explanation:

1290+456

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3 years ago
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Two non-common sides of adjacent supplementary angles form a _____ angle.
mel-nik [20]

Answer:

C. straight

Step-by-step explanation:

 A Linear Pair is two adjacent angles whose non-common sides form opposite rays.

If two angles form a linear pair, the angles are supplementary.

A linear pair forms a straight angle which contains 180º, so you have 2 angles whose measures add to 180, which means they are supplementary.

In the figure given in attachment, AB and BC are two non common sides of ∠ABD and ∠DBC.

∠1 and ∠2 form a linear pair.

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8 0
3 years ago
Select the correct answer.<br> Which graph shows a function and its inverse?
labwork [276]

Answer:

See below

Step-by-step explanation:

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None of the graphs look correct though, but it also seems that some options are cut out, so make sure to choose the correct graph given the characteristics I've previously described.

6 0
2 years ago
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Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
3 years ago
Complete the pattern
romanna [79]
1.) 376.2
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hope that helped
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