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4 years ago

What's the next number 2 3 5 7 11 13 17

Mathematics

2 answers:

Vesnalui [34]4 years ago

8 0

19 is the answer

Hope this helps!

maw [93]4 years ago

4 0

The sequence 2, 3, 5, 7, 11 are the first five prime numbers. A prime number is a positive integer which has exactly 2 positive integer factore, one factor being 1 and the other factor is the positive number itself. So the next prime numbers after 11 are 13, then 17, 19, 23, 29, 31, 37, 41, 43

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per pound 4. Cameron is buying movie tickets for himself and 3 friends. He spends $32. How much did each ticket cost? per ticket

Sholpan [36]

Answer: 32 divided by 4 = 8

It costs - $8 for each ticket

Step-by-step explanation:

32divided by 4=8 therefore the amount of each ticket is $8

7 0

3 years ago

Se van a unir dos tramos de cadena: uno mide 0.75 m de largo y el otro 15/100 de metro . ¿Cual será la longitud total ya que est

likoan [24]

Step-by-step explanation:

It is given that,

The length of section 1 is 0.75 m and the length of section 2 is 15/100 m. The total length of the section is equal to the sum of section 1 and section 2. So, we will add them as follows :

$l=0.75\ m+\dfrac{15}{100}\ m\\\\\because \dfrac{15}{100}=0.15\\\\l=0.75\ m +0.15\ m\\\\l=0.9\ m$

So, the length of the section is 0.9 m or 9/10 m

8 0

4 years ago

Which of the lengths does Cecil repeat?how many times does he repeat?

Aliun [14]

A year is a leap year (and only if)

He repeats it about 3 times

6 0

4 years ago

the numerator of a fraction x/y is 2 less than the denominator. If 3 is added to both the numerator and denominator, then the su

Mashutka [201]

Answer:

Step-by-step explanation:

Fraction :x/y

numerator x = y - 2

Now the fraction can be written as: (y-2)/y

3 is added to both denominator and numerator.

After adding 3, the new fraction = $\frac{y-2 +3 }{y + 3 } = \frac{y+ 1 }{y +3}$

The sum of the new fraction and the original fraction is 53/35

$\frac{y+1}{y+3} + \frac{y-2}{y} = \frac{53}{35}\\\\\frac{(y+1)*y}{(y+3)*y}+\frac{(y-2)*(y+3)}{y(y+3)}=\frac{53}{35}\\\\\frac{y^{2}+y}{y^{2}+3y}+\frac{y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{y^{2}+y+y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{2y^{2} + 2y - 6}{y^{2}+3y}=\frac{53}{35}\\\\$

35*(2y² + 2y - 6) = 53 *(y² + 3y)

35*2y² + 2y * 35 - 6*35 = 53 *y² + 53*3y

70y² + 70y - 210 = 53y² + 159y

70y² + 70y - 210 - 53y² - 159y = 0

70y² - 53y² + 70y - 159y - 210 = 0

17y² - 89y - 210 = 0

6 0

3 years ago

Read 2 more answers

5.) A 10-foot ladder is placed against a vertical wall such that the bottom of the ladder is

anygoal [31]

If x is the distance the base of the ladder is from the wall, and y is the distance to top of the ladder is up the wall, then the Pythagorean theorem tells you

... x² + y² = 10²

Differentiating with respect to time, we have

... 2x·dx/dt + 2y·dy/dt = 0

... dy/dt = (-x/y)·dx/dt

We are given x = 6 ft and dx/dt = 3 ft/s. Using the first equation, we can find y as

... y = √(10² -6²) = 8

Then

... dy/dt =(-6/8)·(3 ft/s)

... dy/dt = -2.25 ft/s

The top of the ladder is sliding down the wall at -2.25 ft/s.

7 0

3 years ago