Find the slope of the given line, if it is defined.

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

Answer: A. The slope is $-\dfrac{4}{3}$ .

Step-by-step explanation:

The slope of a line helps to specify the direction of the line.

The slope of a line that passes through (a,b) and (c,d) is given by :-

$\text{Slope}=\dfrac{d-b}{c-a}$

Then the slope of a line passes through origin i.e. (0,0) and (-9,12) is given by :-

$\text{Slope}=\dfrac{12-0}{-9-0}\\\\\Rightarrow\ \text{Slope}=\dfrac{12}{-9}\\\\\Rightarrow\ \text{Slope}=-\dfrac{4}{3}$

Hence, the slope is $-\dfrac{4}{3}$ .

You might be interested in

PLEASE HELP

poizon [28]

Part A
The given line passes through (-2,2) and it is parallel to the line

$4x - 3y - 7 = 0$

We need to determine the slope of this line by writing it in slope -intercept form.

$3y = 4x - 7$

$y = \frac{4}{3} x - \frac{7}{3}$
The slope of this line is
$\frac{4}{3}$

The line parallel to this line also has slope

$m = \frac{4}{3}$

The equation is

$y = \frac{4}{3} x + c$

We substitute (-2,2)

$2 = \frac{4}{3}( - 2) + c$

$c = 2 + \frac{8}{3} = \frac{14}{3}$

The required equation is

$y = \frac{4}{3} x + \frac{14}{3}$

PART B

The given line is

$4x - 3y - 7 = 0$

The slope of this line is
$\frac{4}{3}$

The slope of the line perpendicular to it is

$m = - \frac{3}{4}$

The equation of the line is

$y = - \frac{ 3}{4} x + c$

We substitute the point, (-2,2)

$2= - \frac{ 3}{4} ( - 2) + c$

$2= \frac{ 3}{2} + c$

$c = 2 - \frac{3}{2} = \frac{1}{2}$

The equation of the perpendicular line is

$y= - \frac{ 3}{4} x + \frac{1}{2}$

6 0

3 years ago

If a coin is flipped 3 times what is the probability of getting heads at least once

Sergio [31]

Answer: 1.5 times

3 flips divided by 2 sides of a coin would be 1.5

this could be wrong

3 0

3 years ago

Read 2 more answers

Four points, E, F, G, and H lie on the coordinate plane. Of the choices given, which two points have the longest

svp [43]