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Ray Of Light [21]
3 years ago
11

How many ounces of a 30% alcohol solution must be mixed with 9 ounces of a 35% alcohol solution to make a 31% alcohol solution ?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

  36 ounces

Step-by-step explanation:

Let q represent the quantity of 30% solution required. The total amount of alcohol in the mix is ...

  30%·q + 35%·9 = 31%·(q +9)

  30q + 315 = 31q +279 . . . . multiply by 100 and eliminate parentheses

  36 = q . . . . . add -(279+30q) to both sides

36 ounces of 30% alcohol must be mixed to make the 31% solution.

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\huge \underline\text {Hello There!!}

<h3><u>Given</u></h3>

Rolled A six-sided dice.

<h3><u>To </u><u>Find </u></h3>

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<h3><u>Solution</u></h3>

Total Possible Outcomes= 1, 2, 3, 4, 5, 6.

So, No. of possible Outcomes= 6

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So, No. of favorable outcomes of Prime number= 3

<h3><u>We Know,</u></h3>

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