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3 years ago

How many ounces of a 30% alcohol solution must be mixed with 9 ounces of a 35% alcohol solution to make a 31% alcohol solution ?

Mathematics

1 answer:

sleet_krkn [62]3 years ago

6 0

Answer:

36 ounces

Step-by-step explanation:

Let q represent the quantity of 30% solution required. The total amount of alcohol in the mix is ...

30%·q + 35%·9 = 31%·(q +9)

30q + 315 = 31q +279 . . . . multiply by 100 and eliminate parentheses

36 = q . . . . . add -(279+30q) to both sides

36 ounces of 30% alcohol must be mixed to make the 31% solution.

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Answer:

XQ = 12

Step-by-step explanation:

In this question it asks for XQ instead of x, but you need to find x first.

1. Find x.

XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)

Solve for x.

3x - 3 = 2(2x - 6)

Distribute 2.

3x - 3 = 4x - 12

Isolate x.

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Divide -1 out.

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Now solve for XQ, which the equation is given.

XQ = 2(9) - 6

XQ = 18 - 6

XQ = 12

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