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3 years ago

A town's population went from 25,800 to 42,600 in 15 years. What was the percent of changes?

1 answer:

8 0

42,600 - 25,800 = 16800. That is the increase in 15 years.

You then calculate the increase as a percentage of the original population; 25,800.

16,800 / 25,800 * 100 = 65.11%

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Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR= 5 m and diagonal QS

svet-max [94.6K]

Answer:

Given the statement: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P.

Properties of Kite:

The diagonals are perpendicular

Two disjoint pairs of consecutive sides are congruent by definition of kite

One diagonal is the perpendicular bisector to the other diagonal.

It is given that: Side QR = 5m and diagonal QS = 6m.

Then, by properties of kite:

$QP = \frac{1}{2}QS$

Substitute the value of QS we get QP;

$QP = \frac{1}{2}(6)$ = 3 m

Now, in right angle $\triangle RPQ$

Using Pythagoras theorem:

$QR^2= RP^2 +QP^2$

Substitute the given values we get;

$(5)^2= RP^2 +(3)^2$

$25= RP^2 +9$

Subtract 9 from both sides we get;

$16= RP^2$

Simplify:

$RP = \sqrt{16} = 4 m$

Therefore, the length of segment RP is, 4m

5 0

3 years ago

Read 2 more answers

PASSAGE:

Art [367]

The shortest distance separating Julio from Sarah is 111.8ft

To know the distance of the shortest bridge between Julio and Sarah, the following procedure must be carried out.

We know that Julio walked 100ft to one side and Sarah walked 20ft to the opposite side, that is, on the <em>y-axis</em> they are 120ft apart.

On the other hand, Julio stayed by the river and Sarah walked 9ft away from the river, that is, on the <em>x-axis</em> they are separated by a distance of 59ft (assuming that the width of the river is 50ft).

To know the linear distance that separates them, it is necessary to use the following formula of the Pythagorean theorem.

c² = a² + b²

c= $\sqrt{a^{2} + b^{2} }$

From this operation we know the value of a and b:

a = 120ft

b = 59ft

Now we just have to replace the values in the formula.

c = $\sqrt{120^{2} + 59^{2} }$

c = $\sqrt{14400 + 3481}$

c = $\sqrt{17881}$

c = 133,7

However, 133.5ft is not the value of the bridge distance because Sarah went 9ft away form the river. Then a portion must be subtracted from her to calculate the exact portion of the distance above the river.

For this we must calculate the distance that separates them that is above the Earth, for this we use the same mathematical formula.

c = $\sqrt{20^{2} + 9^{2} }$

c = $\sqrt{400 + 81}$

c = $\sqrt{481}$

c = 21,9ft

So the distance a part of the Earth covers is 21.9ft. To find out how far the bridge should be over the river, we subtract 21.9ft from the total distance 133.7ft

133,7ft - 21,9ft = 111,8ft

Note: This question is incomplete because it has missing information (the length and width of the river).

Learn more in: brainly.com/question/25292638