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2 years ago

HELP WILL MARK YOU BRAINLIEST, PLS I NEED ASAP

Mathematics

1 answer:

Alenkinab [10]2 years ago

4 0

Answer:

Pizza 1: lenght(l)=16 and width(w)=4

Perimeter=40in.

Pizza 2: l=32 and w=2

Perimeter=68in.

Step-by-step explanation:

1. List down factors of 64.

64=1,2,4,8,16,32,64

2. Select the factors you'll be using to draw your rectangles. In this case I selected the factors 2,4,16 and 32 because area of rectangle=l×w. Therefore 2×32=64 and 4×16=64.

3. Draw your rectangles according to the measurements you chose. If the drawing is too big to fit the box you can simply use a scale. Such as 1 inch=4 inches on your drawing. For example, when drawing the length of the second Pizza which is 32in. you can simply draw a line of 8 inches.

4. After drawing your pizzas you niw have to find the Perimeter of both. Simply use the formula Perimeter of a rectangle=2(l+w)

Pizza 1: Perimeter=2(16+4)

=2×20

=40in.

Now do the same for Pizza 2 using its own lengjt and width. Hope this helped.

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julsineya [31]

Answer:

The first and third is correct.

Step-by-step explanation:

I'm not a expert but I know its right.

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2 years ago

Read 2 more answers

Christine went shopping and bought each of her eighteight nephews a gift, either a video costing $14.95 or a CD costing $16.8

pogonyaev

So I think you should set up an equation like this: 14.95x+16.88y=131.18 , x+y=8

so x=8-y, plug this into the original equation:
14.95(8-y)+16.88y=131.18
Evaluate: 119.60-14.95y+16.88y=131.18
Combine like terms: 119.60+1.93y=131.18
Subtract 119.60 from both sides. You get: 1.93y=11.58
Divide both sides by 1.93. You get y=6

Plug into second equation: x+y=8 ---> x+6=8 and solve for x. x=2

Christine bought 2 video games and 6 CDs. 14.95(2)+16.88(6)=131.18

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2 years ago

you want to purchase a new pair of jeans that cost $48 but on sale for 15% off. what's the sale price?

jekas [21]

40.8 because u take 15 percent of 48 and subtract it from 48

7.2 - 48 = 40.8

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2 years ago

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Maru [420]

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2 years ago

A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7

stepladder [879]

Answer:

6*8=48 groups with elements of order 7

Step-by-step explanation:

For this case the first step is discompose the number 168 in factors like this:

$168 = 8*3*7= 2^3 *3*7$

And for this case we can use the Sylow theorems, given by:

Let G a group of order $p^{\alpha} m$ where p is a prime number, with $m\leq 1$ and p not divide m then:

1) $Syl (G) \neq \emptyset$

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0

2 years ago