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lorasvet [3.4K]
3 years ago
6

a can contains 200 mixed nuts: almonds,cashew and peanuts. If the probability of choosing an almond is 1/10 and the probability

of choosing a cashew is 1/4, how many peanut are in the can?
Mathematics
2 answers:
aleksley [76]3 years ago
5 0
1/10 of 200 is 20
1/4 of 200 is 50
20+50=70
200-70=130 peanuts
Scrat [10]3 years ago
3 0
\frac{1}{10} *200=20 \text{ almonds}\newline \newline \frac{1}{4} *200=50 \text{ cashews} \newline \newline 200-20-50=130 \text{ peanuts}
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Sunny_sXe [5.5K]

Answer:

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3 years ago
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(A) and (D)

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Please help!!!
stiv31 [10]

Answer:

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B

Step-by-step explanation:

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3. Is means equals and of means multiply

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B

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Answer:

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Step-by-step explanation:

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