a can contains 200 mixed nuts: almonds,cashew and peanuts. If the probability of choosing an almond is 1/10 and the probability

Question

3 years ago

6

of choosing a cashew is 1/4, how many peanut are in the can?

2 answers:

Scrat [10]3 years ago

3 0

$\frac{1}{10} *200=20 \text{ almonds}\newline \newline \frac{1}{4} *200=50 \text{ cashews} \newline \newline 200-20-50=130 \text{ peanuts}$

aleksley [76] · Answer 1 · 2022-06-09T18:45:44+03:00

5 0

1/10 of 200 is 20
1/4 of 200 is 50
20+50=70
200-70=130 peanuts