a can contains 200 mixed nuts: almonds,cashew and peanuts. If the probability of choosing an almond is 1/10 and the probability
of choosing a cashew is 1/4, how many peanut are in the can?
2 answers:
1/10 of 200 is 20
1/4 of 200 is 50
20+50=70
200-70=130 peanuts
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