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kkurt [141]
3 years ago
6

How do you add a fraction with different denomirers

Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0
Hey there!
When we're adding with different denominators, our goal is to keep the equivalent fraction, but create like denominators.
Let's think of an easier situation. If we have the number 5 and we want an equivalent number, we multiply by one. It's no different with fractions. We want to multiply by some version of one, like 2/2 or 4/4
For example, if we have:
2/8 + 4/6

Our LCM is 24. Therefore, we multiply 2/8 by 3/3:
2/8(3/3) = 6/24

And 4/6 by 4/4:
4/6(4/4) = 16/24

As you can see, we multiplied by versions of 1, so they're still the same fraction.

We have:
16/24 + 6/24 = 22/24 = 11/12

Hope this helps!
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Serena is making a large meatloaf that contains ground beef and ground pork. The beef is $3.50 per Pound and the pork is $2.00 p
I am Lyosha [343]

Hi there! :)

<u>Answer:</u>

Serena bought 0.75 pounds of pork and about 3.93 pounds of beef.


<u>Step-by-step explanation:</u>

Lets start by laying out the important information we know:

- Beef = $3.50/pound → 1 pound of beef = $3.50

- Pork = $2.00/pound → 1 pound of pork = $2.00

- Buys 0.75 pounds of pork → buys 0.75 of 1 pound of pork

- Buys x pounds of beef

- Spends $15.25 in total → 0.75 pounds of pork + x pounds of beef = $15.25


Once this is done, it's much easier to see what we are dealing with (when it's just a bunch of words it's a lot harder to understand).


<u>Creating your algebraic equation:</u>

Algebraically, your equation needs to be equal to the total amount that Serena spent on pork and beef.

She bought 0.75 of 1 pound of pork, which in other words means that she bought 0.75 of $2.00. The word "of" is the same thing as a multiplication sign. SO, all of this would translate into this: <u>(0.75 × 2)</u>

She then bought beef, but we don't know how much. What we can do is replace the "amount of pounds of beef she bought" with the letter "x". Remember, 1 pound of beef is $3.50. SO, all of this would translate into this: <u>3.50x</u>

Your algebraic equation should look like this:

(0.75 × 2) + 3.50x = 15.25

Now all you need to do is solve this equation by isolating "x":

<u>(0.75 × 2)</u> + 3.50x = 15.25

<u>1.5</u> + 3.50x = 15.25

Subtract 1.5 from each side of the equation → 15.25 - 1.5 = 13.75

<u>3.50</u>x = 13.75

Divide each side of the equation by 3.50 → 13.75 ÷ 3.50 = 3.92857143...

x ≈ 3.93


There you go! I really hope this helped, if there's anything just let me know! :)

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For any graph of the line, the solution set is the points on the line.

Therefore the solution set is the infinite set of points on the line.

The correct solution set for the graph is infinite set of points on the line.

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