20 10 40 30. 15 40 70 25 20 30 100 40 50

KengaRu [80]

To find the area of a rectangle, multiple the width by the length.

(And simply the fractions for a simpler equation)

For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5

(3/4) • (8/5) = area

Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)

The area of piece A is 24/20

If you do the same for piece B:

(2/5) • (21/8) = area

The answer is 42/40

8 0

3 years ago

Read 2 more answers

Last question please

MatroZZZ [7]

Let's try an make a formula to make things easy.

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Look at Andrew's pattern, it goes up 6 every time. Lets look at the 6 times table

6 times table: 6, 12, 18, 24, ...

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First think, how would you work out the 7th term in the 6th times table?

You would do 6 times 7.

So the formula for the 6th times table is:

6n (where n is the term you want to find out)

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So to get the 9th term in the 6 times table, you would replace the n with 9, like so:

9th term in 6 times table = 6 x 9 = 54

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Now lets compare the 6 times table to Andrew's pattern:

6 times table: 6, 12, 18, 24,

Andrew's pattern: 3, 9, 15, 21,

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If you look, you can see that Andrew's pattern is the 6 times table minus 3!

So what would be the formula for Andrew pattern?

---> it would be: 6n - 3 (since it's the 6 times table but minus 3)

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We can use this formula to easily work out the 20th term in Andrew's pattern!:

20th term = 6 x 20 - 3 = 120 - 3 = 117 (remember, replace the n with 20)

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Now let's make a formula for Ben's pattern!

Ben's pattern goes up in 5s, so lets compare it to the 5 times table:

5 times table: 5, 10, 15, 20

Ben's pattern: 3, 8, 13, 18,

The formula for the 5 times table is 5n, and Ben's pattern is the 5 times table but minus 2.

So the formula for Ben's pattern is: 5n - 2

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Now swap out the n for 20 (to get the 20th term):

20th term = 5 x 20 - 2 = 100 - 2 = 98

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So Andrew's 20th term is 117, and Ben's 20th term is 98.

All we do now is subtract them to find the difference:

117 - 98 = 19

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Answer:

Ben's 20th term is smaller by 19!

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5 0

3 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

2 years ago

The ratios of the measures of the angles in a triangle is 3:10:7. Find the measure of the smallest angle. Just write the numeric

Burka [1]

Answer to written question:
3x + 10x + 7x = 180
Combine like terms
20x = 180
Divide by 20
x = 9
Smallest angle 3x = 3*9 = 27 degrees

Answer to question in picture:
30/6x-2 = 36/5x + 13
Cross multiply
30(5x + 13) = 36(6x-2)
Distribute
150x + 390 = 216x - 72
Subtract 150x
390 = 66x - 72
Add 72
462 = 66x
Divide by 66
x = 7

5 0

2 years ago

Read 2 more answers

Determine an equation of a Quadratic function

Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1) 0 = 4a + 2b + c

(2) 0 = 36a + 6b + c

(3) 12 = 9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6) 0 = 8a + b

(7) -4 = 9a - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

0 = -32 + b

(9) b = 32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0

3 years ago

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