A computer company wants to start a call center. They designed a simulation using a random number generator to predict the frequ
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Volume of a sphere and a cone
We have that the equation of the volume of a sphere is given by:
We have that the radius of a sphere is half the diameter of it:
Then, the radius of this sphere is
r = 6cm/2 = 3cm
<h2>Finding the volume of a sphere</h2>We replace r by 3 in the equation:
Since 3³ = 3 · 3 · 3 = 27
If we use π = 3.14:
Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:
4.18666... ≅ 4.19
Then, we have that:
Then, we have that:
<h2>Finding the volume of a cone</h2>We have that the volume of a cone is given by:
where r is the radius of its base and h is the height:
Then, in this case
r = 3
h = 6
and
π = 3.14
Replacing in the equation for the volume:
Then, we have:
3² = 9
Answer: the volume of the cone that has the same circular base and height is 56.52 cm³