D-123 doraa 2 feeet long and yuh
Problem 4:
multiply by 11,
8(n-10) = 64*11
divide by 8,
n-10 = 8*11
Add 10,
n = 88 + 10 = 98
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Problem 5:
-0.6(r+0.2)=1.8
Divide by -0.6,
r+0.2 = -3
subtract 0.2,
r = -3 - 0.2 = -3.2
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Problem 6:
I hope this method isn't too confusing for you,
but I would multiply through by the LCM of the denominators to get rid of the fractions. LCM of 3, 9 and 5 is 45.
Multiply both sides by 45,
(45w - 20)(-30) = -36
Divide -30,
45w - 20 = 36/30
Add 20,
45w = 36/30 + 20
Divide 45 as a final step,
w = 21.2/45
If F(3) then 3=x. So all you would do is substitute 3 in for x