Word expression for 20+5x9

Recall what you know about similarity. If circle B is similar to circle A, what must exist?

kenny6666 [7]

It's not exactly clear what your teacher or book is asking for. By the way, all circles are similar to one another. There's no need to make the statement "If circle B is similar to circle A" because it's something that can be proven for any pair of circles. There are no cases where we can find two circles that are not similar.

4 0

4 years ago

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A certain forest covers an area of 2600 km2. Suppose that each year this area decreases by 7.75%. What will the area be like aft

kakasveta [241]

Answer:

After 15 years, the area will be of 775.3 km²

Step-by-step explanation:

The equation for the area of the forest after t years has the following format.

$A(t) = A(0)(1-r)^{t}$

In which A(0) is the initial area and r is the yearly decrease rate.

A certain forest covers an area of 2600 km2.

This means that $A(0) = 2600$

Suppose that each year this area decreases by 7.75%.

This means that $r = 0.0775$

So

$A(t) = 2600(1-0.0775)^{t}$

$A(t) = 2600(0.9225)^{t}$

What will the area be like after 15 years?

This is $A(15)$

$A(t) = 2600(0.9225)^{t}$

$A(15) = 2600(0.9225)^{15} = 775.3$

After 15 years, the area will be of 775.3 km²

3 0

3 years ago

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Pls helppp me with this!!

zepelin [54]

Answer:4

Step-by-step explanation: Because 4 goes in 3/4 better and more eqvilent to that answer.

7 0

2 years ago

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The mass of a piece of iron pyrite, or "fools gold", is 57.2 g. The volume is 11 cm3. What is the density of the piece of iron p

katen-ka-za [31]

Answer:

Step-by-step explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{57.2}{11} = 5.2 \\$

We have the final answer as

Hope this helps you

3 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago