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2 years ago

3(2/3) of 4 ÷ 2(1/4) + 2/6 - 1/2

Mathematics

1 answer:

Ulleksa [173]2 years ago

4 0

It’s the solution for this question

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The sum of two numbers is 41. The smaller number is 17 less than the larger number. What are the numbers?

Sergio [31]

29 and 12! 29 + 12 comes out to 41 and 29 - 12 comes out to 17. I hope this helps!!

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2 years ago

Determine which prostulate or theorem can be used to prove

REY [17]

Answer:

S.A.S

EXPLANATION:

SQ=SQ(Common side)

<Q=<Q. (Common angle)

PQ=RQ.

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3 0

3 years ago

Simplify the expression. (–2 – c)(–1)

mafiozo [28]

Distribute it, a(b+c) = ab+ac
=(-2-c)(-1)
= (-2)(-1)+(-c)(-1)
= 2+c

6 0

2 years ago

Read 2 more answers

An English professor assigns letter grades on a test according to the following scheme. A: Top 14% of scores B: Scores below the

NeX [460]

Answer:

Grades between 62 and 64 result in a D grade.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 71.9, \sigma = 7.8$

Find the numerical limits for a D grade.

D: Scores below the top 84% and above the bottom 10%

So below the 100-84 = 16th percentile and above the 10th percentile.

16th percentile:

This is the value of X when Z has a pvalue of 0.16. So X when Z = -0.995.

$Z = \frac{X - \mu}{\sigma}$

$-0.995 = \frac{X - 71.9}{7.8}$

$X - 71.9 = -0.995*7.8$

$X = 64$

10th percentile:

This is the value of X when Z has a pvalue of 0.1. So X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 71.9}{7.8}$

$X - 71.9 = -1.28*7.8$

$X = 62$

Grades between 62 and 64 result in a D grade.

6 0

2 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 ? 9x2 ? 108x + 2, [?3, 4]

SVEN [57.7K]

Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints

take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3

test entpoints

f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190

the min is at x=3 and max is at x=-2

4 0

3 years ago

3(2/3) of 4 ÷ 2(1/4) + 2/6 - 1/2​

3(2/3) of 4 ÷ 2(1/4) + 2/6 - 1/2