Answer:
Step-by-step explanation:
ABC and DEF are parallel lines. So, ∠ABE and ∠BED are co interior angles.
∠ABE + ∠BED = 180 {SUM OF CO INTERIOR ANGLE IS 180}
∠ABE+ 110.2 = 180
∠ABE = 180 - 110.2
∠ABE = 69.8
Now, ABC is straight line
∠ABE + ∠EBG + ∠CBG = 180
69.8 + ∠EBG + 34.8 = 180
104.6 + ∠EBG = 180
∠EBG = 180 - 104.6
∠EBG = 75.4
Again, DEF is straight line
∠DEB + ∠BEG + ∠GEF = 180
110.2 + ∠BEG + 25.6 = 180
∠BEG + 135.8 = 180
∠BEG = 180 - 135.8
∠BEG = 44.2
In triangle BEG,
∠BEG + x + ∠EBG = 180 { sum of all angles of triangle is 180}
44.2 + x + 75.4 = 180
x + 119.6 = 180
x = 180 - 119.6
x = 60.4
Answer:
m=9
Step-by-step explanation:
11-9m=-70
-11 -11
-9m = -81
divide both sides by -9 and you get m=9
Question # 14
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am less than 20.
- So the number 'x' must be less than 20 i.e. x < 20
I am more than 13.
- So the number 'x' must be greater than 13 i.e. x > 13
I am less than 17.
- So the number 'x' must be less than 17 i.e. x < 17
Finally:
I am 4 more than 12
i.e. 12+4 = 16
Thus, the number is x = 16
Question # 15
Part a)
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am more than 10.
I am less than 20.
I am more than 12.
I am less than 15.
As the numbers left after all the conditions are fulfilled are 13 and 14.
- But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.
So, from the remaining number 13 and 14;
14 > 13
Thus, the number x = 14
Part b)
Drawing the number 14 in the place value:
Chart
Tens Ones
1 4
Answer:
11) a or d 12) b
Step-by-step explanation:
sorry, I don't feel like looking at number 11 properly I'm half asleep
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
