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krok68 [10]
3 years ago
9

Can someone please help

Mathematics
2 answers:
maria [59]3 years ago
8 0
I would most probably say 204
Brilliant_brown [7]3 years ago
4 0
I'd say either 148 or 204
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11. Write the equation in slope intercept form that has a slope of -23 and passes through the point (-1, 2).
insens350 [35]
11. y = -23x - 21

You can get this by starting with y = mx + b (slope intercept form). Then put in all the knowns and solve for the b. 

2 = -23(-1) + b
2 = 23 + b
-21 = b

Then add that to the end of the equation with m = -23

12. -5

The y-intercept of an equation is always the number added on at the end of an equation. It is also the number with no x attached to it. 

13. 8x^9y^6

When you use the law of exponents, you need to make sure the exponent goes to each individual term. When we cube the 2, it becomes 8. When you cube x^3, you get x^3*x^3*x^3 or x^9. And with y^2 you get y^6 
7 0
2 years ago
What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


5 0
3 years ago
Read 2 more answers
Find the value of x for which
Artyom0805 [142]
B


hope this helps :)
(can you please mark me as brainliest?)
4 0
3 years ago
4 + 4 (1 + 5m) = -132
MrRissso [65]

Answer:

m=-7

Step-by-step explanation:

4+4+20m=-132

8+20m=-132

20m=-132-8

20m=-140

m=-7

6 0
2 years ago
What is 6(2x-8)-9x simplified
Readme [11.4K]

THE ANSWER TO THIS IS 3x-48

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2 years ago
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