During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.148 kg baseball crashing through the pane
1 answer:
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Answer:
The minimum speed must the car must be 13.13 m/s.
Explanation:
The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.
We know that, mg be the weight of car and rider, which is equal to the centripetal force.
So, the minimum speed must the car must be 13.13 m/s.
Answer:
Explanation:
Check attachment for solution.
Generally the movement of the knight is L, i.e (2,1), (1,2),(-1,2),(1,-2) etc.
So using Pythagoras theorem
x^2+y^2=1^2+2^2
x^2+y^2=5
Then, the knight will make one movement when the displacement is √5.
So let take a look at other positions
(1,0),(0,1),(-1,0), (0,-1).
Then, for us to have this kind of movement, the knight has to make 3 movements.
When the displacement is 1, then it will make 3 movement.
Let examine other positions
(2,2) or(-2,-2) or (2,-2) or (-2,2)
When the displacement is √8
Then, the movement of the knight is 4.
Let examine other points
(2,0) or (0,2) or (-2,0) or (0,-2)
When the displacement is 2.
The knight make 2 movement
