Answer:
v_y = 14.55 m/s
Explanation:
given,
height at which gull is flying = 10.80 m
speed of the gull = 6 m/s
acceleration due to gravity = 9.8 m/s²
Relative to the seagull, the x-speed is 0,
because the seagull has the same x-speed.
Only the y-speed counts:
v_y = 14.55 m/s
hence, the speed at which the clam smash the rock is v_y = 14.55 m/s
Answer:
The frequency does not depend on the amplitude for any (ideal) mechanical or electromagnetic waves.
In electromagnetism we have that the relation is:
Velocity = wavelenght*frequency.
So the amplitude of the wave does not have any effect here.
For a mechanical system like an harmonic oscillator (that can be used to describe almost any oscillating system), we have that the frequency is:
f = (1/2*pi)*√(k/m)
Where m is the mass and k is the constant of the spring, again, you can see that the frequency only depends on the physical properties of the system, and no in how much you displace it from the equilibrium position.
This happens because as more you displace the mass from the equilibrium position, more will be the force acting on the mass, so while the "path" that the mass has to travel is bigger, the mas moves faster, so the frequency remains unaffected.
If the distance is proportional to the square of the time, then the distance in 9 seconds will be (9/8)² as long as the distance in 8 seconds.
(9/8)² = 1.265625
(64 ft) · (1.265625) = <em>81 ft. </em>