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Lorico [155]
2 years ago
14

What are the two key guides to drawing a circuit diagram​

Physics
2 answers:
Sloan [31]2 years ago
4 0
Jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
Brut [27]2 years ago
3 0

Answer:

1) The diagram is drawn with a ruler and a pencil. Always begin by tracing its general shape that is a rectangle. - 2) The standard symbols of the different electric components are located, preferably, in the middle of each side.Jan

Explanation:

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Which description correctly summarizes how an electric motor causes an axle to turn?
Tasya [4]

Answer:

The poles of the magnetic field generated around the armature are attracted to the opposite poles of the permanent magnet. As the opposite poles align, the commutator reverses the current direction so like poles are aligned and the armature continues to spin.

Explanation:

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What are the positive and negative effects of DTT use in society?
Dennis_Churaev [7]

Answer:

Biomagnification

Explanation:

DDT is one of the prime examples of a substance that biomagnifies. I would familiarize yourself with this topic. Hopefully this is a helpful starting point.

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Physics question about density
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7 0
2 years ago
Read 2 more answers
Red light has a wavelength of (7. 21x10^7)m. What is the frequency of this light?
Flura [38]

Answer:

TO answer this question i need wave speed

Explanation:

4 0
1 year ago
An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s
ad-work [718]

Answer:

a

 \theta  =  0.0022 rad

b

 I  =  0.000304 I_o

Explanation:

From the question we are told that  

   The  wavelength of the light is \lambda  = 550 \ nm  =  550 *10^{-9} \ m

    The  distance of the slit separation is  d = 0.500 \ mm = 5.0 *10^{-4} \ m

 

Generally the condition for two slit interference  is  

     dsin \theta =  m \lambda

Where m is the order which is given from the question as  m = 2

=>    \theta  =  sin ^{-1} [\frac{m \lambda}{d} ]

 substituting values  

      \theta  =  0.0022 rad

Now on the second question  

   The distance of separation of the slit is  

       d =  0.300 \ mm  =  3.0 *10^{-4} \ m

The  intensity at the  the angular position in part "a" is mathematically evaluated as

      I  =  I_o  [\frac{sin \beta}{\beta} ]^2

Where  \beta is mathematically evaluated as

       \beta  =  \frac{\pi *  d  *  sin(\theta )}{\lambda }

  substituting values

     \beta  =  \frac{3.142  *  3*10^{-4}  *  sin(0.0022 )}{550 *10^{-9} }

    \beta  = 0.06581

So the intensity is  

    I  =  I_o  [\frac{sin (0.06581)}{0.06581} ]^2

   I  =  0.000304 I_o

3 0
3 years ago
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