Answer:
the observed frequency will reduce but the wavelength will increase
Explanation:
As we know
fo = fs (v/(v-vs))
fo = observed frequency
vs = velocity of source
As per this equation,
When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.
Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase
Given:
Water, 2 kilograms
T1 = 20 degrees Celsius, T2 = 100
degrees Celsius.
Required:
Heat produced
Solution:
Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2 kilograms (4.184 kiloJoules
per kilogram Celsius) (100 degrees Celsius – 20 degrees Celsius)
<u>Q (heat) = 669.42 Joules
</u>This is the amount of heat
produced in boiling 2 kg of water.
Answer:
![a=\frac{v-u}{t} \\a = \frac{0-250}{12} = -20.83 m/s](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D%20%20%5C%5Ca%20%3D%20%5Cfrac%7B0-250%7D%7B12%7D%20%3D%20-20.83%20m%2Fs)
Explanation:
you mean deceleration right ? because the acceleration is 250m/s
Explanation:
In the given situation two forces are working. These are:
1) Electric force (acting in the downward direction) = qE
2) weight (acting in the downward direction) = mg
Therefore, work done by all the forces = change in kinetic energy
Hence,
It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight and the above equation will be as follows.
![(1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2 }](https://tex.z-dn.net/?f=%281.6%20%5Ctimes%2010%5E%7B-19%7D%20%5Ctimes%201000%29%20%5Ctimes%20%28%5Cfrac%7B0.10%7D%7B100%7D%29%20%3D%200.5%20%5Ctimes%209.1%20%5Ctimes%2010%5E%7B-31%7D%20%5Ctimes%20v%5E%7B2%0A%7D)
v = ![sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}](https://tex.z-dn.net/?f=sqrt%7B%5Cfrac%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D%7B%280.5%20%5Ctimes%209.1%20%5Ctimes%2010%5E%7B-31%7D%29%7D)
= 592999 m/s
Since, the electron is travelling downwards it means that it looses the potential energy.
At point C because it is at the lowest position.