The lowest common denominator of 1/3 and 2/9 = 9
Let the side of one square be x.
The maximum perimeter will be when the squares will be lined end to end.
This will be:
x + 9x + 9x + x
= 20x
The perimeter of the figures formed will be less than or equal to 20x.
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
=
[ 2a₁ + (n - 1)d ]
where a₁ is the initial value and d the common difference
Given
=
[ 10 + (n - 1)3 ]
Then by comparison
2a₁ = 10 ( divide both sides by 2 )
a₁ = 4 ← initial value
and d = 3 ← common difference
Thus
=
[ 10 + (7 × 3) ]
= 4(10 + 21)
= 4 × 31
= 124
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