If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
Answer:
3 and 4
Step-by-step explanation:
Consider squares on either side of 15, that is 9 and 16, so
<
<
, that is
3 <
< 4
Answer:
Standard form of the equation is:
∴
Step-by-step explanation:
Given equation:

To convert the given equation to standard form of equation:

Using distribution.


Adding 2 both sides.


Adding
to both sides.

∴
Answer:
Linear Equations In One Variable =
Next step :
in the equation y/6 = 156, it would be equivalent to y = 156 × 6.
so that :
y = 156 × 6
y = 936
this equation solved. (Answer : 936)