If <a=90 or <b=90 or < c=90 the triangle is right
if one of the angles is > 90 the triangle is obtuse
if all the angles are < 90 the triangle is acute
Answer:
x = 1.71
Step-by-step explanation:
![x^3-20=-15\\x^3=-15+20\\x^3=5\\\sqrt[3]{x^3} =\sqrt[3]{5} \\x=1.71](https://tex.z-dn.net/?f=x%5E3-20%3D-15%5C%5Cx%5E3%3D-15%2B20%5C%5Cx%5E3%3D5%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%5Csqrt%5B3%5D%7B5%7D%20%5C%5Cx%3D1.71)
The answer is option c.
That is, the wrong step in step 6. It was written that the center of the circunference is the point (2.1). However, the general equation of a circumference is:
(X- (a)) ^ 2 + (Y- (b)) ^ 2 = r ^ 2
Where the point (a, b) is the center of the circle.
So for this case the point for the center is: (-2, -1)
Answer:
Step-by-step explanation:
4) parallel because 118° is a supplement to 62° and the corresponding angles are both 118°
5) NOT parallel. The labeled angles sum to 120° and would sum to 180° for parallel lines.
6) NOT parallel. see pic.
If parallel, extending a line to intersect ℓ₁ makes an opposite internal angle which would also be 48°. The created triangle would have its third angle at 180 - 90 - 48 = 42° which is opposite a labeled 48° angle, which is false, so the lines cannot be parallel
7)
b = 78° as it corresponds with a labeled angle above it
a = 180 - 78 = 102° as angles along a line from a common vertex sum to 180
f = is an opposite angle to 180 - 78 - 44 = 58° as angles along a line from a common vertex sum to 180
e = 180 - 90 - 64 = 26° as angles along a line from a common vertex sum to 180
c = 58° as it corresponds with f
d = 180 - 58 = 122° as angles along a line from a common vertex sum to 180