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MAVERICK [17]
2 years ago
14

How many grams of CO are needed to react with 3.34 g of Fe2O3?

Chemistry
1 answer:
IRISSAK [1]2 years ago
8 0
How many grams of CO are are needed to react with 3.34g of fe203?
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Moles of phosphorous in 15-35-15 fertilizer in 10g
guapka [62]

<span>The composition of a fertilizer is usually express in NPK number. NPK number is in terms of Percent by mass of the said element which are Nitrogen, Phosphorus and Potassium. A 15-35-15 fertilizer has 15% Nitrogen, 35% Phosphorous, and 15% Potassium by mass. If you have 10 g of this fertilizer, to get the number of moles of phosphorus, you multiply the mass by 35%, which is equal to 10*0.35 or 3.5 g phosphorus. Then you divide the calculated mass of phosphorous by its molar mass which is 30.97 g/mol. Therefore, you have 3.5/30.97 which is equal to 0.1130 mol Phosphorus. This is the amount of Phosphorus in moles in the fertilizer.</span>

6 0
3 years ago
You need to produce a buffer solution that has a pH of 5.31. You already have a solution that contains 10. mmol (millimoles) of
Karolina [17]

Answer:

37 mmol of acetate need to add to this solution.

Explanation:

Acetic acid is an weak acid. According to Henderson-Hasselbalch equation for a buffer consist of weak acid (acetic acid) and its conjugate base (acetate)-

pH=pK_{a}(acetic acid)+log[\frac{mmol of CH_{3}COO^{-}}{mmol of CH_{3}COOH }]

Here pH is 5.31, pK_{a} (acetic acid) is 4.74 and number of mmol of acetic acid is 10 mmol.

Plug in all the values in the above equation:

5.31=4.74+log[\frac{mmol of CH_{3}COO^{-}}{10}]

or, mmol of CH_{3}COO^{-} = 37

So 37 mmol of acetate need to add to this solution.

3 0
2 years ago
Which two types of consumers are known as “nature’s clean-up crew”? Why are they important?
NeTakaya

Fungus: Important because it breaks up several dead leaves, particles, etc, and puts nutrients back in the ground.

Carnivores: eat dead animals, no stinky rotten meat around.

3 0
3 years ago
Read 2 more answers
A plate moves 200 m in 10,000 years. What is its rate in cm/year?
Varvara68 [4.7K]

Answer:

The answer is

<h2>2 cm/year</h2>

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

<h2>\frac{20000}{10000}</h2>

<u>Reduce the fraction with 10,000</u>

We have the final answer as

<h3>2 cm/year</h3>

Hope this helps you

3 0
2 years ago
What is the Arrhenius definition of an acid
matrenka [14]

The answer to your question is,

An Arrhenius acid is a type of substance that separates in water to form Hydrogen ions.

-Mabel <3

8 0
3 years ago
Read 2 more answers
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