Answer:
about 19 or 20 g
Explanation:
To do this, is neccesary to watch a solubility curve of this compound. This is the only way that you can know how many grams are neccesary to dissolve this compound in 50 mL of water to a given temperature.
Now, if you watched the attached graph, you can see the solubility curve of many compounds in 100 g of water (or 100 mL of water). So, to know how many do you need in 50 mL, it's just the half.
So watching the curve, you can see that at 20 °C, we simply need between 35 g and 40 g. Let's just say we need 38 grams of NH4Cl to be dissolved in 100 mL of water.
So, in 50 mL, it's just the half. So, we only need 19 g or 20 g of NH4Cl at 20 °C, to dissolve this compound in water.
Ethers have a tetrahedral geometry i.e. oxygen is sp
3
hybridized. The C−O−C bond angle is 110
o
. Because of the greater electronegativity of O than C, the C−O bonds are slightly polar & are inclined to each other at an angle of 110
o
, resulting in a net dipole moment. This bond angle greater than that of tetrahedral bond angle of 109
o
28
′
. This is due to the fact that internal repulsion by the hydrocarbon part is greater than the external repulsion of the lone pair of oxygen.
Answer:
- 40.66
- 9.91
Explanation:
For the first question:
Our theoretical compound is MR₂
1 mol of MR₂ contains 1 mol of M and 2 moles of R
Let's find out the molar mass:
9.45 g/mol + 18.12 g/mol . 2 = 45.69 g/mol
We can solve this, by an easy rule of three:
1 mol of MR₂ weighs 45.69 grams
Then, 0.89 moles may weigh 40.66 g
For the second question:
Our theoretical compound is D₂G
Let's determine the molar mass:
11.45 g/mol . 2 + 44.57 g/mol = 67.47 g/mol
1 mol of anything contains 6.02×10²³ molecules. By this definition we can say that 6.02×10²³ molecules weigh 67.47 grams. Let's solve by the rule of three:
6.02×10²³ molecules weigh 67.47 g
8.84×10²² molecules may weigh (8.84×10²² . 67.47 ) / 6.02×10²³ = 9.91 g
I don’t know what the answer is just need points sorry
Answer:
One
Explanation:
The formulas for the two acids are CH₃CH₂COO-H and CH₃CH₂CH₂COO-H.
The key factors to consider are the polarities of the C-H and O-H bonds.
A. C-H bonds
The difference in electronegativity is ΔEN =|2.55 - 2.20| = 0.35.
This difference of so small that we usually consider the C-H bond to be nonpolar.
It is extremely unlikely that a C-H bond will dissociate onto ions.
B. O-H bonds
The difference in electronegativity is ΔEN =|3.44 - 2.20| = 1.24.
Thus, an O-H bond is highly polar covalent — the bond has about 32 % ionic character.
It is much more likely that an O-H bond will go all the way and dissociate onto ions.
RCOOH + H₂O ⇌ RCOO⁻ + H₃O⁺
The Kₐ for an O-H bond is about 10⁴⁶ times that of a C-H bond.
Only the O-H bond of a carboxylic acid will dissociate,
