Answer:
(x+5/2)^2 = 0
Step-by-step explanation:
4 x^{2} +20x +25 =0
Divide by 4
4/4 x^{2} +20/4x +25/4 =0
x^2 +5x +25/4 =0
Subtract 25/4 from each side
x^2 +5x +25/4 -25/4 =-25/4
x^2 +5x =-25/4
Take the coefficent of x
5
Divide by 2
5/2
Square it
25/4
Add it to each side
x^2 +5x +25/4 =-25/4+25/4
(x+5/2)^2 = 0
Take the square root of each side
x+5/2 = 0
x = -5/2
Lcm because a multiple is always greater then a factor.
When u multiply these two u should get 6i^2+25i+14.
Construct<span> a perpendicular from the </span>incenter<span> to one side of the triangle to locate the exact radius. 3. place compass point at the </span>incenter<span> and measure from the center to the point where the perpendicular crosses the side of the triangle</span>
<span><span> r = -1/3 = -0.333
</span><span> r = 0</span></span>
