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3 years ago

Can anyone help me with the calculations for the Frequency, Wavelength, Energy Chart?

Chemistry

1 answer:

sergeinik [125]3 years ago

3 0

Use the following equations to fill the chart.

E = hf
where
h = 6.63 x 10⁻³⁴ J/s, Planck's constant
f = frequency Hz
E = quanta of energy, J

c = fλ
where
c = 3 x 10⁸ m/s, the velocity of light
λ = wavelength, m

If energy is given in J/mmol, divide by Avogadro's number, N = 6.02 x 10²³, to convert it to J.

The completed table is shown below.

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Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wo

kozerog [31]

Answer:

The correct answer is A Energy leaves the iron bar and enters the wood until the temperature are equal.

Explanation:

According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.

Here iron bar is placed in wood block energy is transferred from iron bar to wood until the temperatures are equal.

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3 years ago

If you add oil to water and shake the two liquids together what will you form

dalvyx [7]

There will be oil bubbles because oil is more dense than water so therefore they would not mix

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3 years ago

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Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note the

joja [24]

The first step is to balance the equation:

C3H8 + 5O2 ---> 3CO2 + 4H2O

Check the balance

element left side right side

C 3 3
H 8 4*2 = 8
O 5*2=10 3*2 + 4 = 10

Then you have the molar ratios:

3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O

Now you have 40 moles of O2 so you make the proportion:

40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.

Answer: option D. 24.0 mol CO2

7 0

3 years ago

Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentratio

velikii [3]

Answer: The amount of CO that is occupied in the room is $1.98\times 10^3L$

Explanation:

We are given:

Concentration of CO = $8.00\times 10^2ppm=800pm$ by volume

This means that $800\mu L\text{ or }800\times 10^{-6}$ of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

$V=10.99\times 18.97\times 11.89=2478.83m^3$

Converting this into liters, by using conversion factor:

$1m^3=1000L$

So, $2478.83m^3=2.479\times 10^6L$

Applying unitary method:

In 1 L of blood, the amount of CO present is $800\times 10^{-6}$

So, in $2.479\times 10^6L$ of blood, the amount of CO present will be = $\frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L$

Hence, the amount of CO that is occupied in the room is $1.98\times 10^3L$

8 0

3 years ago

The ____ particles of an atom which are called electrons

blsea [12.9K]

Answer:

Subatomic particles

Explanation:

I hope it helped

5 0

3 years ago