Answer:
Electrons are present around the nucleus.
Explanation:
The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.
Symbol= e⁻
Mass= 9.10938356×10⁻³¹ Kg
It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.
He constructed the glass tube and create vacuum in it. He applied electric current between electrodes. He noticed that a ray of particles coming from cathode to wards positively charged anode. This ray was cathode ray.
Properties of cathode ray:
The ray is travel in straight line.
The cathode ray is independent of composition of cathode.
When electric field is applied cathode ray is deflected towards the positively charged plate.
Hence it was consist of negatively charged particles.
While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.
Symbol of proton= P⁺
Symbol of neutron= n0
Mass of proton=1.672623×10⁻²⁷ Kg
Mass of neutron=1.674929×10⁻²⁷ Kg
All these three subatomic particles construct an atom. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
6+2=115 and its good it took test
<u>Answer:</u> The parent isotope is undergoing alpha decay.
<u>Explanation:</u>
A nuclear reaction is defined as the reaction in which the changes in the nucleus of an atom take place and usually form a different element. An unstable nucleus undergoes various decay processes to attain stability.
Alpha decay is a type of decay process that happens when a heavy nucleus decays into a light nucleus with the release of an alpha particle. This alpha particle carries a charge of +2 units and has a mass of 4 units. It is also known as the helium nucleus. The general equation for this decay process is:
It is given that the daughter isotope formed has atomic number 2 less than the parent isotope. Thus, it is undergoing alpha decay.
Answer is: 34,35 mL.
Reaction: Ca + 2H₂O → Ca(OH)₂ + H₂
m(Ca(OH)₂) = 98,5g.
n(Ca(OH)₂) = m÷M = 98,5g÷74g/mol = 1,33mol.
From reaction: n(Ca):n(Ca(OH)₂) = 1:1.
n(Ca) = n(Ca(OH)₂) = 1,33mol.
m(Ca) = n(Ca)·M(Ca) = 1,33mol·40g/mol = 53,24g.
d(Ca) = <span>1.55 g/mL.
V(Ca) = m(Ca)</span>÷d(Ca) = <span>53,24g</span>÷1.55 g/mL = 34,35 mL.