All categories

2 years ago

What is the equation of a vertical line passing through the point (3, -5)?

Mathematics

1 answer:

katen-ka-za [31]2 years ago

6 0

Answer: Format of equation of vertical line: x = (x-coord of passing point.).

ANS : D.

You might be interested in

Find the distance between the points (-7.2, -9.3) and (-7.2, -1.1)

AlexFokin [52]

Answer:

8.2

Step-by-step explanation:

-7.2 to -7.2 is 0

-9.3 to -1.1 is 8.2

Pythagorean theorem is a^2+b^2=c^2

0^2=0

8.2^2=67.24

0+67.24=0

√67.24=8.2

The distance between the to points is 8.2

6 0

2 years ago

What is the ratio of 7/8

ch4aika [34]

Answer:

86.5%

Step-by-step explanation:

6 0

2 years ago

Convert the following unsigned binary number to unsigned decimal.<br><br> 110011.101

tangare [24]

Answer:

51.625

Step-by-step explanation:

Given a unsigned binary number, to calculate the unsigned decimal:

first, starting at dot, you list the positive powers of 2 from right to left beginning in $2^{0}$ that is equal to “1”. Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers: $2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ .

Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in $2^{-1}$ that is equal $\frac{1}{2}$ = 0.5. so you get: $2^{-1}$ $2^{-2}$ $2^{-3}$

Now, join two parts and you get:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

Then, you write the equivalent of each of the power below from corresponding binary digit, like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

_______________________________________

32 16 0 0 2 1 0.5 0 0.125

32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625

So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625

5 0

3 years ago

PLEASE HELP I HATE THIS SM I WANNA KMSS

dedylja [7]

Answer:

you want to flip the original coordinates and make them both negative so (x,y) would become (-y,-x) so in your problem here Q' would be (0,-7), R' would be (-5,-8), S' would be (-10,-7) and T' would be (-5,-2). Hope that helped :>

Step-by-step explanation:

6 0

2 years ago

Select all values of x that make the inequality -x + 8 ≥11 true.

mash [69]

-x + 8 ≥ 11

-x ≥ 3

x ≤ -3

Hope this helps! ;)

8 0

3 years ago