I think it's agriculture.
Answer:
D
Explanation:
This involves a dihybrid inheritance I.e. two genes are being passed on. During meiosis, specifically, the Prophase stage, homologous chromosomes (similar but non-identical chromosomes received from each parent) line side by side. According to the question, one chromosome contains A and B alleles and its homologue, received by the other parent carries a and b alleles. This means that the diploid individual has a genotype AaBb for that gene.
According to Mendel's law of independent assortment, the alleles separate independently of one another into gametes. I.e. allele A and a separates into the gametes without affecting alleles B and b of the other gene.
Crossing-over, which is the exchange of chromosomal segment occurs between the two homologues. Hence, the exchange of chromosomal segments containing alleles in the individual will possibly produce four gametes with the genotypes: AB, Ab, aB, ab.
It developed everyones body
PALISADE CELLS ARE CELLS FOUND WITHIN THE MESOPHYLL IN LEAVES OF DICOTYLED ON PLANTS.THEY CONTAIN CHLLORPLASTS,WHICH CONVERT THE ENERGY STORED IN PHOTONS TO CHEMICAL ENERGY THROUGH PHOTOSYNTHESSIS,WHICH IS MADE UP OF TWO MIN STAGES;THE LIGHT DEPENDENT REACTIONS AND LIGHT INDEPENT REACTIONS
Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%