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3 years ago

What is the perimeter of this rectangle?

Mathematics

1 answer:

Slav-nsk [51]3 years ago

5 0

The perimeter of a rectangle si length + length + width + width or 2l + 2w. Substitute your values in to get 2(70) + 2(65) → 140 + 130 → 270 feet

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irinina [24]

Answer:

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Step-by-step explanation:

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2 years ago

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AleksAgata [21]

Answer:

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2 years ago

What does (2x−2)(3x+5) equal?

saw5 [17]

Answer:

6x² + 4x + 10

Step-by-step explanation:

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6x² + 4x + 10 ans.

hope this helps you !

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1 year ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
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\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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7 0

2 years ago

Can you very be kind and answer

Lera25 [3.4K]

area of a circle is PI x r^2

2 = d/2 = 5.4/2 = 2.7 cm

using 3.14 for PI

3.14 x 2.7^2 = 22.89 square inches

360 degree in a circle, shaded area is 180 degree, which is 50%

so 22.89 x .5 = 11.45 cm^2

4 0

2 years ago