All categories

2 years ago

How large is one side of the square garden plot in meters

Mathematics

1 answer:

ruslelena [56]2 years ago

4 0

the correct question in attached figure

Let
A1 -------------------------> area rectangular plot=4*9=36 m²
A2 ------------------------- > area square plot=x²

we have that
A1=A2
A2=x²=36---------------> x=√36=6 m

the answer is 6 m

You might be interested in

Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol

Alchen [17]

Answer:

$y = 6\cdot z$

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

$x$ - Number of times that Jason volunteered at pet shelter.

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

$y = 3\cdot x$

Jason and Keith

$x = 2\cdot z$

The relationship between the number of times Noah and Keith volunteered is:

$y = 6\cdot z$

7 0

3 years ago

Help please, I don't understand!!! D:

ch4aika [34]

The answer is 2 hours because from 5 to 7 the temperature was raising

4 0

3 years ago

Read 2 more answers

Graph the relation in the table. Then use the vertical-line test. Is the relation a function? Type your answer in the blank to t

zepelin [54]

The answer is C hope this helped u out

7 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$