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Gre4nikov [31]
3 years ago
13

Roger says that 10% of a number will always be less than 25% of any other number. Complete one inequality to support Roger's cla

im and one to show that he is incorrect.
Mathematics
2 answers:
mariarad [96]3 years ago
8 0

Answer:

Roger says that 10% of a number will always be less than 25% of any other number.

Lets say the number are 20 and 50.

When it is correct:

10% of 20 = 0.10\times20=2

25% of 50 = 0.25\times50=12.50

We can see that 10% of 20 is less than 25% of 50.

When it is not correct:

10% of 50 = 0.10\times50=5

25% of 20 = 25\times20=5    

We can see that the answer is equal here.

So, this claim is not correct that 10% of a number will always be less than 25% of any other number. It can be greater also.

musickatia [10]3 years ago
7 0
Roger is only correct if you are talking about the same number.
10%of 100 is 10 while 25% of 100 is 25. Ok, roger, you win this round.
However, if you are talking about different numbers, it will vary.
25% of 4 is 1 while 10% of 1000 is 100. In this case, the 10% of 1000 is bigger than the 25% of 4.
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c

Step-by-step explanation:

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The correct answer is D.

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It has been suggested that night shift-workers show more variability in their output levels than day workers (σ2N &gt; σ2D). Bel
Murljashka [212]

Answer:

<em>Calculated |t |= 7.72 > 2.1314 at 0.05 level of significance </em>

<em>Null hypothesis is rejected </em>

<em> The night shift-workers show more variability in their output levels are greater than day workers </em>

Step-by-step explanation:

<u>Step(i):</u>-

Given first sample size n₁ = 9

Given mean of the first sample x₁⁻ = 520

Given sample variance of the first sample'S²₁' = = 38

Standard deviation of the first sample 'S₁' = √38 =6.16

Given second sample size n₂ = 8

Given mean of the second sample x₂⁻ = 540

Given sample variance of the second sample ( 'S²₂' = 20

Standard deviation of the second sample 'S₂' = √20 = 4.4712

<u><em>Step(ii):-</em></u>

<em>Null hypothesis :H₀:  σ²₁ =σ²₂</em>

<em>Alternative Hypothesis:H₁: σ²₁ > σ²₂</em>

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S^2_{1} }{n_{1} }+\frac{S^2_{2} }{n_{2} }  } }<em></em>

<em>              </em>

            t = \frac{520 - 540 }{\sqrt{\frac{38 }{9 }+\frac{20 }{8 }  } }

           t =    - 7.72

          |t| = |- 7.72| = 7.72

Degrees of freedom

<em> ν = n₁ + n₂ -2 = 9 +8 -2 = 15</em>

<em>t₀.₀₅ = 2.1314</em>

<u><em>Final answer</em></u><em>:-</em>

<em>Calculated |t |= 7.72 > 2.1314 at 0.05 level of significance </em>

<em>Null hypothesis is rejected </em>

<em> The night shift-workers show more variability in their output levels are greater than day workers </em>

4 0
3 years ago
Find the equation of the ellipse with the following properties. The ellipse with foci at (0, 6) and (0, -6); y-intercepts (0, 8)
sesenic [268]
Hi, thank you for posting your question here at Brainly.

The general equation of a horizontal ellipse is

(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.

If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,

2b = 16
b = 8
b^2 = 64

The distance between the two foci is 2c. Thus,

2c = 12
c = 6
c^2 = 36

Then, a2 = 64 + 36 = 100. Substituting to the general equation:

x^2/100 + y^2/64 = 1
8 0
3 years ago
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