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Paraphin [41]
3 years ago
10

3. Ordered: 30 mg Furosemide Available: 40 mg/2ml. How many milliliters will be given?

Chemistry
1 answer:
Ad libitum [116K]3 years ago
3 0

1.5ml of furosemide solution, half of acetanimophen tablet and 6ml of Rocephin will be given.

Explanation:

The furosemide injection contains a concentration of 40mg/2ml of the injectable. The patient, according to his body weight needs an amount of 30mg of furosemide. So he will need 2*30/40 ml of the injectable = 1.5ml of the injectable.

The acetanimophen tablet has an active composition of 500mg. But the patient needs the amount of 250mg of acetanimophen. So the patient will take 250/500 tablets =0.5 tablet.

The Rocephin injectible contains a concentration of 500mg/10ml of the injectable. But the patient needs 300mg of Rocephin. So he will take 10*300/500= 6ml of the injectable.

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3 years ago
Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)
beks73 [17]

The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

#SPJ1

4 0
2 years ago
Read 2 more answers
What happened to the limewater in<br> the experiment? What does this<br> prove?
tensa zangetsu [6.8K]

Explanation:

In the reaction above, we clearly see that a chemical reaction took place but what kind of reaction you might ask?

Looks like it is Thermal decomposition of copper carbonate because decomposition reaction takes place due to the added heat. Decomposition in simple terms in chemical breakdown and here this result is obtained by adding heat.

1) What happened to the lime water?

Although not pictured above, but my assumption is that lime water turned milky or turbid because when CO2 comes in presence of limewater they react to form a percipitate of Calcium carbonate which is the milky color that you get.

2) What does this prove?

- My understanding would be that it proves that CO2 was formed, and that most metal carbonates undergo thermal decomposition into metal oxide and carbon dioxide, and also that a reaction took place since new products were made.

3 0
3 years ago
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