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3 years ago

Which shows the correct steps in the formation of an ionic bond between these atoms?

Physics

2 answers:

aksik [14]3 years ago

6 0

Answer:

The question is not complete. Although, the question below matches your kind of question.

Which shows the correct order of steps during the formation of an ionic bond?

A. Electrons are transferred → Ions form → Ions are attracted to each other

B. Ions form → electrons are transferred

C. Ions are attracted to each other → Electrons are transferred

D. Ions form → electrons are transferred → Ions are attracted to each other

The correct answer is option (A) Electrons are transferred → Ions form → Ions are attracted to each other

Explanation:

Ionic bond is a kind of bond formed when a positively charged ion react with a negatively charged ion.

It involves the transfer of electron. One donate and one receive to complete the electron in it's outermost shell.

So, there is transfer of electrons, formation of bond and attraction of ions

Minchanka [31]3 years ago

5 0

Bonds between ions and compounds mark the formation of hydrogen bonds

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A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its

Nostrana [21]

Answer:

Its speed is maximum and its acceleration is zero

Explanation:

- Concerning the speed:

In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:

$E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2$

where k is the spring constant, x is the displacement, m is the mass and v is the speed.

We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.

- Concerning the acceleration:

According to Newton's second law, the acceleration of the system is proportional to the net force:

$a=\frac{F}{m}$

the net force is just the restoring force of the spring, given by Hooke's law:

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$a=-\frac{kx}{m}$

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