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3 years ago

2 questions that I am just curious about!!! WILL NAME YOU BRAINLIEST!!! Hope you can figure out!! Worth 11 points!!

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

#1: Most likely it does so, and calls other paramedics to help the person it was on its way to go help. But usually people will stay out of its way when they hear one coming...

#2: Probably, because they usually just don't want meat, and don't have problems with things such as crackers. I doubt that they can live solely from vegetables!! It seems impossible!!

I have to say they are some quite interesting questions. Interesting to think over... :) Anyway, I hope my answers help answer yours!!

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Why is the use of scientific names important in biology?

Dafna11 [192]

Scientifc names are important because they allow people around the world to communicate accurately about animal species.

7 0

3 years ago

77. The first law of motion applies to

Mama L [17]

In the first law, an object will not change its motion unless a force acts on it. So I think the answer is A. Only objects that are moving.

8 0

3 years ago

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is th

Alja [10]

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy= $E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')$

Using the formula

Change in internal energy of hammerhead= $m(u_2-u_1)=0$

Change in total energy= $\frac{1}{2}(25)(50)^2+25\times 9.8(-1)$

Where $g=9.8m/s^2$

Change in total energy= $31005 J=\frac{31005}{1000}=31.005 KJ$

1 KJ=1000 J

3 0

3 years ago

Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr

Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

$W = dP + dK\\$

Where

$dP$ = Change in Potential Energy

$dK$ = Change in Kinetic Energy

Change in Potential Energy

$P_{i} = mgh_{i}\\ P_{f} = mgh_{f}$

Where

$P_{i}$ = Initial Potential Energy

$P_{f}$ = Final Potential Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$h_{i}$ = Initial Height = 0

$h_{f}$ = Final Height = 30 m

Inputting the values we get the answer for $dP$

$dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000$

Change in Kinetic Energy

$K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2$

Where

$K_{i}$ = Initial Kinetic Energy

$K_{f}$ = Final Kinetic Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$v_{i}$ = Initial Velocity = 0 m/2

$v_{f}$ = Final Velocity = 4 m/s

Inputting the values we get the answer for $dK$

$dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000$

Total Work

$W = dP + dK\\$

Inputting the values

$W = 2943000 + 80000$

$W = 3,023,000$

a) Finding the useful Power Output

$P = \frac{W}{t}$

Where

$P$ = Power Output

$W$ = Work Done = 3,023,000J

$t$ = Time = 12s

Inputting the values

$P = \frac{3,023,000}{12}\\ P = 251,916.667$

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0

4 years ago

According to Newton’s first law of motion, when will an object at rest begin to move?

Natasha_Volkova [10]

Newton's first law of motion says something like "An object remains
in constant, uniform motion until acted on by an external force".

Constant uniform motion means no change in speed or direction.
If an object changes from rest to motion, that's definitely a change
of speed. So it doesn't remain in the state of constant uniform
motion (none) that it had when it was at rest, and that tells us
that an external force must have acted on it.

8 0

4 years ago

Read 2 more answers